A player caught a cricket ball of mass 150g moving at a rate of 20m/s. If the catching process is completed in 0.1 s, the force of the blow exerted by the ball on the hand of the player is equal to
A
150 N
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B
3 N
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C
30 N
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D
300 N
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Solution
The correct option is C 30 N This is a question based on impulse momentum theorem. |F.Δt| = |change in momentum| ⇒F×0.1=|Pf−Pi|
As the ball will stop after being caught, Pi=mvi=0.15×20=3,Pf=0 ⇒F×0.1=3 ⇒F=30N