A player caught a cricket ball of mass 150 g moving at a rate of 20 m/s. If the catching process is completed in 0.1 s, the force of the blow exerted by the ball on the hand of the player is equal to

30 N

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300 N

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150 N

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3 N

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Solution

The correct option is A
30 N

$F = \frac{Δ p}{Δ t} = 0.15 \times \frac{(20 - 0)}{0.1}$

F = 30 N

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A player caught a cricket ball of mass 150 g moving at a rate of 20 m/s. If the catching process is completed in 0.1 s, the force of the blow exerted by the ball on the hand of the player is equal to

The correct option is A 30 N F=ΔpΔt=0.15×(20−0)0.1 F = 30 N

The correct option is A
30 N

$F = \frac{Δ p}{Δ t} = 0.15 \times \frac{(20 - 0)}{0.1}$

F = 30 N