Question

A plot of kinetic energy of the emitted electron against frequency of the incident radiation yields a straight line. The slope of the straight line is:

• A. $0.66\times {10}^{-35}$
• B. $0.66\times {10}^{-33}$
• C. $0.33\times {10}^{-33}$
• D. $3.33\times {10}^{-35}$

Answer 1

The correct option is B $0.66\times {10}^{-33}$

Relation between kinetic energy and frequency is $E=\varphi -h\nu$.

here slope is $h$ = planck's constant h = $6.62\times {10}^{-34}$

So, answer is B