Question

A point mass is executing simple harmonic motion with an amplitude of 10 mm and frequency of 4 Hz. The maximum acceleration ($m/s^2$) of the mass is

Answer 1

$f_n=\frac{{\omega }_n}{2\times \pi }$
$\Rightarrow {\omega }_n=2\pi f=2\times 3.14\times 4=25.12$ rad/s
$a_{max}={\omega }_n^{2}x=(25.12{)}^2\times 10\times {10}^3=$ 6.31 $m/s^2$