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Question

A point object is placed at a distance of 10 cm and its real image is formed at a distance of 20 cm from a concave mirror. If the object is moved by 0.1 cm towards the mirror the image will shift by (nearly)

A
0.4 cm away from the mirror
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B
0.8 cm away from the mirror
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C
0.4 cm towards the mirror
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D
0.8 cm towards the mirror
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Solution

The correct option is A 0.4 cm away from the mirrorFrom the relation, 1v+1u=1f By differentiation mirror formula we have, −dvv2−duu2=0 dv=v2u2(−du) From given data, ⇒dv=(2010)2(0.1)=0.4 cm As the change in the final distance is positive so the image will shift away from the mirror. Why this question? Caution: We can use differential formula only for small changes in object position

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