A point P 3-4 is reflected in line x -3-0- Then the image of P isA- -8-4B- -9-4C- -6-4D- -5-4

The correct option is B ( 9, 4) Given line x + 3 = 0 ⇒ x = 3 Let P' (x, 4) be the image of P(3, 4), Using midpoint formula x+3/2= 3 ⇒ x= 9 ...

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Standard VI

Mathematics

Image of a Point with Respect to X = a

A point P 3,4...

Question

A point P(3, 4) is reflected in line x + 3 = 0. Then the image of P is

(-8, 4)

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(-9, 4)

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(-6, 4)

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(-5, 4)

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Solution

The correct option is B
(-9, 4)

Given line x + 3 = 0 $\Rightarrow$ x = -3

Let P' (x, 4) be the image of P(3, 4), Using midpoint formula

$\frac{x + 3}{2} = - 3 \Rightarrow x = - 9$

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A point P(3, 4) is reflected in line x + 3 = 0. Then the image of P is

The correct option is B (-9, 4) Given line x + 3 = 0 ⇒ x = -3 Let P' (x, 4) be the image of P(3, 4), Using midpoint formula x+32=−3 ⇒x=−9

The correct option is B
(-9, 4)

Given line x + 3 = 0 $\Rightarrow$ x = -3

Let P' (x, 4) be the image of P(3, 4), Using midpoint formula

$\frac{x + 3}{2} = - 3 \Rightarrow x = - 9$