A point P is 26 cm away from the centre O of a circle and the length PT of the tangent drawn from P to the circle is 10 cm. Find the radius of the circle.

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Solution

Join the points O,P,T .It forms like a triangle whose hypotenuse is 26cm altitude is 10cm then
Base = (2626) - (1010)
= 576
Radius = $\sqrt{576}$
= 24

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A point P is 26 cm away from the centre O of a circle and the length PT of the tangent drawn from P to the circle is 10 cm. Find the radius of the circle.

Join the points O,P,T .It forms like a triangle whose hypotenuse is 26cm altitude is 10cm then Base = (26*26) - (10*10) = 576 Radius = √576 = 24

Join the points O,P,T .It forms like a triangle whose hypotenuse is 26cm altitude is 10cm then
Base = (2626) - (1010)
= 576
Radius = $\sqrt{576}$
= 24