You visited us 1 times! Enjoying our articles? Unlock Full Access!

Byju's Answer

Standard VIII

Physics

Luminous Intensity

A point sourc...

Question

A point source of light is placed at the bottom of a water lake. If the area of the illuminated circle on the surface is equal to $3$ times the square of the lake. The refractive index of water is

\sqrt{π + 1}

No worries! We‘ve got your back. Try BYJU‘S free classes today!

\sqrt{\frac{π}{3} + 1}

Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses

\frac{π}{3} + 1

No worries! We‘ve got your back. Try BYJU‘S free classes today!

\frac{π}{4} + 1

No worries! We‘ve got your back. Try BYJU‘S free classes today!

Open in App

Solution

The correct option is B $\sqrt{\frac{π}{3} + 1}$
Hence, option $(B)$ is correct answer.

Suggest Corrections

Similar questions

Q. A point source is at a depth of 1 m from the water surface. The diameter of the circle of light rays on water surface refracted into the air will be (refractive index of water is

\frac{4}{3}

)

Q. A pole

4 m

high driven into bottom of a lake is

1 m

above the water. If the incident sun rays make an angle of

53^{\circ}

with the normal at water surface, then the length of the shadow of the pile on the bottom of the lake will be

[

Given refractive index of water

= \frac{4}{3}]

ABCDEF is a jogging track, in which area of the semi-circle BCD is $\frac{5000}{π} m^{2}$ . If OO' is $\frac{100}{π} m,$ Find the area of the shaded region.

Q. The area of a square is equal to the area of a circle. The ratio between the side of the square
and the radius of the circle is

(a)

\sqrt{π}

: 1 (b) 1 :

\sqrt{π}

π

(d)

π

: 1

Q. A square lawn has a circular pond in the centre. Find the shaded region's area given that the diameter of circle is

\frac{1}{3}

times the diagonal of square with sides 3 cm.

Join BYJU'S Learning Program

A point source of light is placed at the bottom of a water lake. If the area of the illuminated circle on the surface is equal to 3 times the square of the lake. The refractive index of water is

The correct option is B √π3+1Hence, option (B) is correct answer.

A point source of light is placed at the bottom of a water lake. If the area of the illuminated circle on the surface is equal to $3$ times the square of the lake. The refractive index of water is

The correct option is B $\sqrt{\frac{π}{3} + 1}$
Hence, option $(B)$ is correct answer.