Question

A pole 6 m high casts a shadow $2\sqrt{3}$ m long on the ground, then find the angle of elevation of the sun.

Answer 1

Let the pole height be $AB=6m$ and its shadow height $AB=2\sqrt{3}$
Since $\tan \theta =\frac{AC}{AB}$
$\tan \theta =\frac{6}{2\sqrt{3}}$
$\tan \theta =\sqrt{3}$
$\therefore \theta ={60}^{\circ }$