A pole stands vertically, inside a scalene triangular park ABC. If the angle of elevation of the top of the pole from each corner of the park is same, then in Δ ABC, the foot of the pole is at the?
A
Centroid
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B
circumcentre
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C
incentre
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D
orthocentre
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Solution
The correct option is A circumcentre
OD is the vertical rule
∠DOA=∠DOB=90
Given ∠OAD≤∠OBD
OD is common to both angle AOD and BOD
Hence triangles AOD, BOD are congruent
∴OA=OB
OA=OC
Therefore$ O is equidistant from A, B, C so circumcentre.