Question

A polyhedron has $6$ vertices and $8$ faces. How many edges does it have?

Answer 1

Given that,

Faces = $8$

Vertices = $6$

use the formula,

$$\begin{gathered} V+F-E=2 \\ 6+8-E=2 \\ 14-E=2 \\ E=14-2 \\ E=12 \end{gathered}$$

Hence, the number of edges is $12$.