MyQuestionIcon

6

You visited us 6 times! Enjoying our articles? Unlock Full Access!

Mole Concept & Avogadro Number

A polythene b...

Question

A polythene bag of $3$ litre capacity is filled by helium gas (Occupying $11$ at $0.3$ atm & $300$ K) at $300$ K. Subsequently enough $N e$ gas is filled to make total pressure $0.4$ atm at $300$ K. Calculate ratio of moles of $N e$ to $H e$ in container.

Open in App

Solution

Mole fraction= $H_{A} = \frac{P_{A}}{P_{A} + P_{B}}$
For $\frac{N e}{H e} = \frac{3}{4}$
$= 0.75$ .

Suggest Corrections

thumbs-up

0

Similar questions

Q. A polythene bag 3 litre capacity is partially filled by 1 liter of Helium gas at 0.3 atm at 300K. Subsequently, enough

N e

gas is filled to make total pressure 0.4 atm at 300K. Calculate ratio of moles of

N e

H e

in the container.

Q. A polythene bag of

3

litre capacity is filled by Helium gas (occupying

L i

0.3 a t m

300 K

300 K

. Subsequently enough

N e

gas is filled to make total pressure

0.4 a t m

300 K

. Calculate ratio of moles of

N e

H e

Q. A polythene bag of 3 liter capacity is tilled by Helium gas (Occupying 1L at 0.3 atm & 300K ) at 300K. Subsequently enough Ne gas is tilled to make total pressure 0.4 atm at 300K. Calculate ratio of moles of Ne to He in container.

g

O_{2}

was filled in a container of capacity 8.21 litres at 300

K

. Calculate Pressure exerted by

O_{2}

a t m

.( Write your answer after multiplying 10 .

Q. Calculate the compressibility factor for a gas, if

1

mole of it occupy

0.821 litre

300 K

50 atm

.

View More

Join BYJU'S Learning Program

similar_icon

Related Videos

lock

CHEMISTRY

Watch in App

explore_more_icon

Explore more

Mole Concept & Avogadro Number

Standard IX Chemistry

Join BYJU'S Learning Program

CrossIcon