Question

Calculate the compressibility factor for a gas, if $1$ mole of it occupy $0.821\text{litre}$ at $300\text{K}$ and $50\text{atm}$.

• A. $1$
• B. $1.33$
• C. $1.67$
• D. $0.67$

Answer 1

The correct option is C $1.67$

We know,
Compressibility factor, $\left(Z\right)=\frac{P{V}_{\text{real}}}{nRT}$
where,
$P=$Pressure (in $\text{atm}$)
$V_{\text{real}}=$ Volume of real gas (in $\text{L}$)
$n=$ number of mole
$T=$ temperature
$R=0.0821\text{atm-L/mol-K}$

So, $Z=\frac{50\times 0.821}{1\times 0.0821\times 300}=1.67$
Gas is more compressible than ideal gas.