A pond is in shape of trapezium. A bridge is to be constructed such that the bridge is perpendicular to the parallel sides. It is given that the area of the pond is 1080 $m^{2}$ and the lengths of its parallel sides are 55.6 m and 34.4 m. Find the length of the bridge.

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24 m

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48 m

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50m

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Solution

The correct option is B
24 m

Area of trapezium = h $\frac{(a + b)}{2}$ sq. units

Let the length of bridge be x

The length of the bridge required is the distance between the parallel sides of the trapezium.

Thus, $\frac{1}{2} \times (55.6 + 34.4) \times x = 1080 m^{2}$

$\Rightarrow x = 24 m$

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A pond is in shape of trapezium. A bridge is to be constructed such that the bridge is perpendicular to the parallel sides. It is given that the area of the pond is 1080 m2 and the lengths of its parallel sides are 55.6 m and 34.4 m. Find the length of the bridge.

The correct option is B 24 m Area of trapezium = h(a+b)2 sq. units Let the length of bridge be x The length of the bridge required is the distance between the parallel sides of the trapezium. Thus, 12×(55.6+34.4)×x=1080m2 ⇒x=24m

A pond is in shape of trapezium. A bridge is to be constructed such that the bridge is perpendicular to the parallel sides. It is given that the area of the pond is 1080 $m^{2}$ and the lengths of its parallel sides are 55.6 m and 34.4 m. Find the length of the bridge.

The correct option is B
24 m

Area of trapezium = h $\frac{(a + b)}{2}$ sq. units

Let the length of bridge be x

The length of the bridge required is the distance between the parallel sides of the trapezium.

Thus, $\frac{1}{2} \times (55.6 + 34.4) \times x = 1080 m^{2}$

$\Rightarrow x = 24 m$