Question

A population which is in Hardy-Weinberg equilibrium has $1600$ individuals. If dominant allelic frequency is $0.7$, then find out the number of dominant individuals in that population.

• A. $144$
• B. $672$
• C. $784$
• D. $1456$

Answer 1

The correct option is A $144$

From Hardy-Weinberg equilibrium, p + q = 1,

q = 1 – p = 1 – 0.7 = 0.3

q2 =0.3 *0.3=0.09

The homozygous dominant individuals are represented by

1600 *p =1120

1600*q=144

So, the correct option is '144'