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Question

A positive charge is passing through an electromagnetic field is which E and B are directed toward y-axis and z- axis respectively. If a charge particle passes through the region undeviated, then its velocity is/are represented by (here a,b, and c are constant)


A

v=EBi^+aj^

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B

v=EBi^+bk^

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C

v=EBi^+ci^

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D

v=EBi^

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Solution

The correct option is B

v=EBi^+bk^


Step 1: Given data

A charged particle is introduced at the origin, (x=0,y=0,z=0).

Initial velocity is v, uniform electric filed is E and uniform magnetic field is B.

We have to find the cases where the particle will move in a straight line with constant velocity.

Step 2: Find the cases where the particle will move in a straight line with constant velocity.

To move a particle with constant velocity,

Fnet=0

So,

The electric force = magnetic force

qE=qvB

E=vB

v=EB

Only positive charged particles with speed EB can get through.

Hence, option B is correct answer.


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