A potential difference of $20 K V$ is applied across an $X - r a y$ tube. Find the minimum wavelength of $X - r a y$ generated

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Solution

$F = \frac{[1.6 X 1 0^{- 19} X 2 X 104]}{6.63 X 1 0^{- 34}}$

$= 4.82 X 1018$ ㎐

Therefore, the wavelength $= \frac{C}{F}$

$= 0.621 X 1 0^{- 10} m$

= 0.621nm is the answer.

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