A potential difference of 300 volts is applied to a combination of 2.0μF and 8.0μF capacitors connected in series. The charge on the 2.0μF capacitor is :
A
2.4×10−4coulomb
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B
4.8×10−4coulomb
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C
7.2×10−4coulomb
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D
9.6×10−4coulomb
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Solution
The correct option is B4.8×10−4coulomb We know when capacitor are connected in series charge present on them must be equal. In seris 1Cs=1C1+1C2 1Cs=12+18 1Cs=5.8 Cs=85μF Q=CV Q=85×10−6×300 Q=4.8×10−4C.