1
You visited us 1 times! Enjoying our articles? Unlock Full Access!
Question

# A potentiometer wire has length 10 m and resistance 10Ω. It is connected to a battery of EMF 11 volt and internal resistance 1Ω, then the potential gradient in the wire is

A
10 V/m
No worries! We‘ve got your back. Try BYJU‘S free classes today!
B
1 V/m
Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses
C
0.1 V/m
No worries! We‘ve got your back. Try BYJU‘S free classes today!
D
none
No worries! We‘ve got your back. Try BYJU‘S free classes today!
Open in App
Solution

## The correct option is D 1 V/mR=resistance of potentiometer wire=10ΩL=length of potentiometer wire=10mr=internal resistance of cell=1ΩV=emf of cell=11VEffective resistance of circuit=Req=R+r⟹Req=10+1=11ΩCurrent in circuit=I=VReq=1111⟹I=1APotential difference across ends of potentiometer wire AB=Vo=IR⟹Vo=1×10=10VPotential gradient of potentiometer= VoL=1010=1V/mAnswer-(B)

Suggest Corrections
0
Join BYJU'S Learning Program
Related Videos
emf and emf Devices
PHYSICS
Watch in App
Explore more
Join BYJU'S Learning Program