A potentiometer wire is 100 cm long and a constant p.d. is maintained across it. Two cells A and B are connected in series first and then in opposition. The balance points were obtained at 50 cm and 30 cm. Find the ratio of the e.m.f.s of the cells.
A
1:2
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B
3:2
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C
4:1
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D
3:5
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Solution
The correct option is C 4:1 E1E2=l1+l2l1−l2=50+3050−30=8020=41E1:E2=4:1