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Question

A power transformer is used to set up an alternating emf of 220V to 4.4kV to transmit 6.6kW of power. The primary coil has 1000 turns. What is current rating of secondary? (Assume efficiency 100%)

A
2.5A
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B
1.5A
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C
1.0A
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D
0.75A
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Solution

The correct option is A 1.5A
Power of transformer =V1I1=V2I2V2=4.4kVsecondaryvoltageratingI2=secondarycurrentratingP=V2I26.6kW=4.4kVI2I2=6.64.4=1.5A


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