Question

An ideal transformer converts $220Va.c.to3.3$ k.V a.c to transmit a power of $4.4$ kW. If primary coil has $600$ turns, then alternating current in secondary coil is

• A. $1/3$A
• B. $4/3$A
• C. $5/3$A
• D. $7/3$A

Answer 1

The correct option is B $4/3$A

Assuming no loss in power transmission:-

$E_1{I}_1=E_2{I}_2$

$⟹I_2=\frac{E_1}{E_2}{I}_1$

$E_1=220V$ and ,$E_2=3.3kV=3300V$

Now, $P=E_1{I}_1$

$⟹I_1=\frac{P}{E_1}=\frac{4.4\times {10}^3}{220}=20A$

Hence, $I_2=\frac{220}{3300}\times 20$

$⟹I_2=1.3A$