Question

A transformer has 100 turns in the primary coil and carries 8 A current. If input power is 1 kW, the number of turns in secondary coil to have 500 V output will be:

• A. 100
• B. 200
• C. 400
• D. 300

Answer 1

Answer: (C)

400

Power $=V.I$

$1000=500I$

$\left(I\right)$ secondary $=2$ A

Now, $\frac{I_1}{I_2}=\frac{N_2}{N_1}\Rightarrow \frac{8}{2}=\frac{N_2}{100}$

$\Rightarrow N_2=400$.