Question

A power transformer is used to step up an alternating e.m.f. of 220 V to 11 kV to transmit 4.4 kW of power. If the primary coil has 1000 turns, what is the current rating of the secondary ? Assume 100% efficiency for the transformer

• A. 2 A
• B. 1.7 A
• C. 0.4 A
• D. 0.8 A

Answer 1

The correct option is C 0.4 A

We know that

$i_s=\frac{P_s}{V_s}$

Thus, substituting the values, we get:-

$i_s=\frac{4.4\times {10}^3}{11\times {10}^3}{i}_s=0.4A$