A power transmission line feeds input power at $2300 V$ to a step down transformer with its primary windings having $4000$ turns, giving the output power at $230 V$ . If the current in the primary of the transformer is $5 A$ , and its efficiency is $90 %$ , the output current would be:

20 A

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50 A

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45 A

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25 A

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Solution

The correct option is C $45 A$
$P o w e r_{o u t} = V_{2} I_{2} = η \times P o w e r_{i n} = \frac{90}{100} \times 2300 \times 5$
$I_{2} = \frac{90 \times 23 \times 5}{230} = 45 A$

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Q. A power transmission line feeds input power at

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A power transmission line feeds input power at 2300 V to a stepdown transformer with its primary windings having 4000 turns. What should be the number of turns in the secondary in order to get output power at 230 V?

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A power transmission line feeds input power at 2300 V to a step down transformer with its primary windings having 4000 turns, giving the output power at 230 V. If the current in the primary of the transformer is 5 A, and its efficiency is 90%, the output current would be:

The correct option is C 45 APowerout=V2I2=η×Powerin=90100×2300×5I2=90×23×5230=45A

A power transmission line feeds input power at $2300 V$ to a step down transformer with its primary windings having $4000$ turns, giving the output power at $230 V$ . If the current in the primary of the transformer is $5 A$ , and its efficiency is $90 %$ , the output current would be:

The correct option is C $45 A$
$P o w e r_{o u t} = V_{2} I_{2} = η \times P o w e r_{i n} = \frac{90}{100} \times 2300 \times 5$
$I_{2} = \frac{90 \times 23 \times 5}{230} = 45 A$