Question

A project consists of six activities. The immediate predecessor of each activity and the estimated duration is also provided in the table below:

Activity	Immediate predecessor	Estimated duration (weeks)
P	-	5
Q	-	1
R	Q	2
S	P, R	4
T	P	6
U	S, T	3

If all the activities other than S take the estimated amount of time, the maximum duration (in weeks) of the activity S without delaying the completion of the project is

• A. 6

Answer 1

The correct option is A 6


Hence different paths are:

$\text{P - T - U = 5 + 6 + 3 = 14 weeks}\leftarrow \text{Critical path}$

$\text{P - Dummy - S - U = 5 + 4 + 3 = 12 weeks}$

$\text{Q - R - S - U = 1 + 2 + 3 + 4 = 10 weeks}$

$\because \text{Only 'S' is delayed and no other activity is delayed.}$

So, maximum activity time for activity 'S' can be 6 weeks without delaying the project.