A projectile can have the same range R for two angles of projection. If t1 and t2 be the time of flight in the two cases then prove that t1t2=2R/g
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Solution
For a projectile having same range for two angle of projection , both angles should be complementary to each other, i.e, if one angle is α, then other will be β=900−α
so, t1=2usinαg and t2=2usinβg=2usin(900−α)g=2ucosαg