Question

A projectile has maximum range of $200$m. what is the maximum height attained by it.

• A. $25m$
• B. $50,m$
• C. $75m$
• D. $100m$

Answer 1

The correct option is B $50,m$

Given, $Range=200m$

So, The maximum range:

For $\theta ={45}^0$ Range is maximum,

$R_{max}=\frac{u^{2}sin2\theta }{g}=\frac{u^2}{g}$

Thus the maximum height,

$H_{max}=\frac{u^{2}si{n}^2\theta }{2g}=\frac{u^2}{g}\times \frac{si{n}^2{45}^0}{2}=200\times (\frac{1}{2}{)}^2=50m$