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Question

A projectile is fired at an angle of 45 with the horizontal. Elevation angle of the projectile at its highest point as seen from the point of projection is

A
tan1(32)
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B
45
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C
60
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D
tan112
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Solution

The correct option is D tan112

Let α be the elevation angle
tan α=HR/2.......(i)
By using the relation, 4H=Rtanθ
HR=tan θ4......... (ii)
Using (i) and (ii), we get
tanα=tanθ2
tanα=tan452
α=tan1(12)

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