You visited us 1 times! Enjoying our articles? Unlock Full Access!

Byju's Answer

Standard XII

Physics

Introduction to Projectile Motion

A projectile ...

Question

A projectile is fired from the surface of the earth with a velocity of $5 m/s$ at an angle $θ$ with the horizontal. Another projectile, fired from another planet with a velocity of $3 m/s$ at the same angle, follows a trajectory which is identical with the trajectory of the projectile fired from the earth. The value of acceleration due to gravity on the planet (in $m s^{- 2}$ ) is $({Given g = 9.8 ms}^{- 2})$

3.5

Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses

5.9

No worries! We‘ve got your back. Try BYJU‘S free classes today!

16.3

No worries! We‘ve got your back. Try BYJU‘S free classes today!

110.8

No worries! We‘ve got your back. Try BYJU‘S free classes today!

Open in App

Solution

The correct option is A $3.5$
Lets assume the value of acceleration due to gravity on the planet is $g_{p}$ .

$y = x tan θ - \frac{g x^{2}}{2 u^{2} {cos}^{2} θ}$

For the trajectory of both the projectiles to be same, the ratio $\frac{g}{u^{2}}$ should be equal, as every other variable is same.

$∴ \frac{g}{u_{e}^{2}} = \frac{g_{p}}{u_{p}^{2}}$
$\frac{9.8}{5^{2}} = \frac{g_{p}}{3^{2}}$

$g_{p} = 3.5 m / s^{2}$

Suggest Corrections

Similar questions

Q. A projectile is fired from the surface of the earth with a velocity of

5 m/s

at an angle

θ

with the horizontal. Another projectile, fired from another planet with a velocity of

3 m/s

at the same angle, follows a trajectory which is identical with the trajectory of the projectile fired from the earth. The value of acceleration due to gravity on the planet (in

m s^{- 2}

) is

({Given g = 9.8 ms}^{- 2})

Q. A projectile is fired from the surface of the earth with a velocity of

5 {ms}^{- 1}

and angle

θ

with the horizontal. Another projectile fired from another planet with a velocity of

3 {ms}^{- 1}

at the same angle follows a trajectory which is identical with the trajectory of the projectile fired from the earth. The value of the acceleration due to gravity on the planet (in

{ms}^{- 2}

) is
(Given

g = 9.8 {ms}^{- 2}

)

Q. A projectile is fired from the surface of the earth with a velocity of

5 m s^{- 1}

and angle

8^{\circ}

with the horizontal. Another projectile fired from another planet with a velocity of

3 m s^{- 1}

at the same angle follows a trajectory which is identical with the trajectory of the projectile fired from the earth. The value of the acceleration due to gravity on the planet is:

(g i v e n = 9.8 m s^{- 2})

A projectile is fired from the surface of the earth with a velocity of $5 {ms}^{- 1}$ and angle $θ$ with the horizontal. Another projectile fired from another planet with a velocity of $3 {ms}^{- 1}$ at the same angle follows a trajectory which is identical with the trajectory of the projectile fired from the earth. The value of the acceleration due to gravity on the planet (in ${ms}^{- 2}$ ) is

(Given $g = 9.8 {ms}^{- 2}$ )

Q. A projectile is fired from the surface of the earth with a velocity of

5 m s^{- 1}

and angle

θ

with the horizontal. Another projectile fired from another planet with a velocity of

3 m s^{- 1}

at the same angle follows a trajectory which is identical with the trajectory of the projectile fired from the earth. The value of the acceleration due to gravity on the planet is (in

m s^{- 2})

is
(Given

g = 9.8 m s^{- 2}

)

Join BYJU'S Learning Program

The correct option is A 3.5Lets assume the value of acceleration due to gravity on the planet is gp. y=xtanθ−gx22u2cos2θ For the trajectory of both the projectiles to be same, the ratio gu2 should be equal, as every other variable is same. ∴gu2e=gpu2p 9.852=gp32 gp=3.5 m/s2