Question

A projectile is fired horizontally with a velocity of $98m/s$ from the top of a hill $490m$ high. Find the distance of the point where the particle hits the ground from foot of the hill.

Answer 1

Given : $u_x=98m/s$ $a_y=g=9.8m/s^2$

Height of the hill $S_y=h=490$ m

$\therefore$ Time of flight $T=\sqrt{\frac{2h}{g}}=\sqrt{\frac{2\left(490\right)}{9.8}}=10$ s

Distance BA (or horizontal range) $BA=u_{x}T=98\times 10=980m$