A projectile is fired with a speed u at an angle θ with the horizontal. Its speed when its direction of motion makes an angle α with the horizontal is
A
usecθcosα
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B
usecθsinα
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C
ucosθsecα
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D
usinθsecα
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Solution
The correct option is Cucosθsecα
Let v be the speed of projectile when its direction of motion makes an angle α with horizontal. As the horizontal component of velocity remains constant during projectile motion. ⇒vcosα=ucosθ ⇒v=ucosθsecα