Question

A projectile is fired with initial speed of $10\text{m/s}$ making an angle ${30}^{\circ }$ with horizontal. Which of the following option is correct?

• A. Range of projectile is $5\sqrt{3}\text{m}$
• B. Maximum height attained by projectile is $1.25\text{m}$
• C. Time of flight of projectile is $1\text{sec}$
• D. All of these

Answer 1

The correct option is D All of these


We know,
Range of projectile $R=\frac{v^2\sin 2\theta }{g}=\frac{{10}^2\times \sin {60}^{\circ }}{10}=5\sqrt{3}\text{m}$
Max. height, $H_{\text{max}}=\frac{v^2{\sin }^2\theta }{2g}$
$=\frac{{10}^2\times {\sin }^2{30}^{\circ }}{20}$
$=1.25\text{m}$
Time of flight, $T=\frac{2v\sin \theta }{g}$
$=\frac{2\times 10\times \sin {30}^{\circ }}{10}$
$=1\text{sec}$
$\therefore$ Option (d) is correct.