A projectile is moving at 60 m/s at its highest point, where it breaks into two equal parts due to an internal explosion. One part moves vertically up at 50 m/s with respect to ground, the part will move at speed of :
A
110m/s
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B
120m/s
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C
130m/s
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D
10√61m/s
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Solution
The correct option is C10√61m/s Momentum conservation in y direction p,p1 and p2 are momentum before collision and after collision p=0p1y=50 momentum conservation in x direction p=60p1y=0 sop2y=60 p2=√502+602 p2=10√61