A projectile is projected at an angle 45^° to horizontal. If H is the maximum height and R is the horizontal range, then relation between H and R is

Open in App

Solution

Suggest Corrections

Similar questions

Q. A stone projected with a velocity

u

at an angle

θ

with the horizontal reaches maximum height

H_{1}

. When it is projected with velocity

u

at an angle

(\frac{π}{2} - θ)

with the horizontal, it reaches maximum height

H_{2}

. The relation between the horizontal range

R

of the projectile,

H_{1}

and

H_{2}

Q. In case of a projectile if the maximum vertical height H is equal to horizontal range R then angle of projection

θ

Q. If

R

and

H

represent horizontal range and maximum height of the projectile, then the angle of projection with the horizontal is:

A stone projected with a velocity u at an angle $θ$ with the horizontal reaches maximum height $H_{1}$ . When it is projected with velocity u at an angle $(\frac{π}{2} - θ)$ with the horizontal, it reaches maximum height $H_{2}$ .
The relation between the horizontal range R of the projectile, $H_{1}$ and $H_{2}$ is

Q. The horizontal range and maximum height attained by a projectile are

R

and

H

, respectively. If a constant horizontal acceleration

a = \frac{g}{4}

is imparted to the projectile due to wind, then its horizontal range and maximum height will be

Join BYJU'S Learning Program