A projectile is thrown upwards with a velocity v at an angle theta with the vertical.Its average velocity between the instants it crosses half the maximum height is:
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Solution
Here the angle theta (here denoted as A ) is made with the vertical. Therefore vertical component of velocity be v cosA and horizontal component of velocity be v sinA. There is no effect of vertical component of velocity in this motion. Because of body moves with a constant speed of v sinA in horizontal direction, the average velocity during this displacement will be v sinA in horizontal direction.