The correct option is A It travels vertically with a velocity of 40 ms−1 at all times.
uy=usinθ=50sin53∘=50×45=40 ms−1
We know, vy=usinθ−gt (during upward journey) and vy=gt (during downward journey).
So, vy first decreases and then increases during the projectile motion.
Hence, option (a) is incorrect
ux=ucosθ=50×35=30 ms−1
As the horizontal component remains constant. Thus, option (b) is correct
Velocity is minimum when its vertical component becomes 0 ⇒umin=ucosθ=30 ms−1
Since vy=gt for downward motion, option (d) is also correct.