A projectile thrown with velocity v making angle θ with vertical gains maximum height H in the time for which the projectile remains in air, the time period is
A
√Hsinθg
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B
√Hcosθg
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C
√4Hg
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D
√8Hg
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Solution
The correct option is D√8Hg Maximum height, H=v2sin2(90−θ)2g......(i)
Time of flight, T=2vsin(90−θ)g......(ii)