A - B 2 and when A -8- B -2If B -5- then find the value of A-A- 50B- 10C- 25D- 100

The correct option is A 50Given, A ∝ B^2 Let the constant of variation be k. ⇒ A = kB^2 Given, at A = 8, B = 2. So,k = A/B^2 = 8/2^2 = 8/4 = 2. Hence, at B = ...

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Byju's Answer

Standard VIII

Mathematics

Variation

A ∝ B 2 and w...

Question

$A \propto B^{2}$ and when A = 8, B = 2.
If B = 5, then find the value of A.

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Solution

The correct option is A 50
$G i v e n, A \propto B^{2}$
Let the constant of variation be k.
$\Rightarrow A = k B^{2}$
Given, at A = 8, B = 2.
$S o, k = \frac{A}{B^{2}} = \frac{8}{2^{2}} = \frac{8}{4} = 2.$
Hence, at B = 5, the value of $A = k B^{2} = (2) (5^{2}) = 50.$

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A∝ B2 and when A = 8, B = 2. If B = 5, then find the value of A.

The correct option is A 50Given, A∝ B2 Let the constant of variation be k. ⇒A=kB2 Given, at A = 8, B = 2. So,k=AB2 =822=84=2. Hence, at B = 5, the value of A=kB2=(2)(52)=50.

$A \propto B^{2}$ and when A = 8, B = 2.
If B = 5, then find the value of A.

The correct option is A 50
$G i v e n, A \propto B^{2}$
Let the constant of variation be k.
$\Rightarrow A = k B^{2}$
Given, at A = 8, B = 2.
$S o, k = \frac{A}{B^{2}} = \frac{8}{2^{2}} = \frac{8}{4} = 2.$
Hence, at B = 5, the value of $A = k B^{2} = (2) (5^{2}) = 50.$