a proton a deuteron and an alpha particle are accelerated by the same potential difference in a uniform magnetic field what is ratio of kinetic energy

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Solution

$Work done = Change in KE qV = KE As V is constant, Ratio of KE = q_{1} : q_{2} : q_{3} = 1 : 2 : 4$

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a proton a deuteron and an alpha particle are accelerated by the same potential difference in a uniform magnetic field what is ratio of kinetic energy

Work done = Change in KEqV=KEAs V is constant, Ratio of KE=q1:q2:q3 =1:2:4

$Work done = Change in KE qV = KE As V is constant, Ratio of KE = q_{1} : q_{2} : q_{3} = 1 : 2 : 4$