A proton is about 1840 times heavier than an electron. When it is accelerated by a potential difference of 1keV, it's kinetic energy will be:
A
1840keV
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B
1/1840keV
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C
1keV
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D
920V
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Solution
The correct option is C1keV When a charge q is accelerated by V its, K.E. will be given by K.E.=qV, irrespective of its mass. Therefore, its K.E. will be 1KeV.