A proton is kept at rest. A positively charged particle is released from rest at a distance $d$ in its field. Consider two experiments; one in which the charged particle is a proton and in another a positron. In the same time $t$ , the work done on the two moving charged particles is

Same as the same force law is involved in the two experiments

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Less for the case of a positron, as the positron moves away more rapidly and the force on it weakens

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More for the case of a positron, as the positron moves away a larger distance

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Same as the work done by charged particle on the stationary proton

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Solution

The correct option is C More for the case of a positron, as the positron moves away a larger distance
Force between two protons $=$ force between a proton and a positron. As positron is much lighter than proton, it moves away a larger distance compared to proton. As work done $= f o r c e \times d i s t a n c e$ , therefore in the same time $t$ , work done in case of positron is more than that in case of proton.

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A proton is kept at rest. A positively charged particle is released from rest at a distance d in its field. Consider two experiments; one in which the charged particle is a proton and in another a positron. In the same time t, the work done on the two moving charged particles is

A proton is kept at rest. A positively charged particle is released from rest at a distance $d$ in its field. Consider two experiments; one in which the charged particle is a proton and in another a positron. In the same time $t$ , the work done on the two moving charged particles is