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Question

A public water supply contains 0.10 ppb (part per billion) of chloroform (CHCl3). How many molecules of CHCl3 would be obtained from 0.478 mL of this water?

A
4×1013×NA
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B
103×NA
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C
4×1010×NA
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D
None of these
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Solution

The correct option is A 4×1013×NA
Density of water = 1 g/mL
Weight of 0.478 mL of water = 0.478 g
Parts per billion =weight of CHCl3(g)total weight of water (g)×1090.10=weight of CHCl30.478×109

Weight of CHCl3=0.10×0.478×109=4.78×1011g
Molar mass of CHCl3=119.5 g/mol
119.5 g of CHCl3 contains NA molecules .
4.78×1011 g will contain = NA119.5×4.78×1011g=4×1013×NA
No. of molecules = 4×1013×NA

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