A pulse travels on a string under tension. The transverse displacement of the string from its equilibrium position is given by y = f (x - 150 t) where x is in meters and t is in seconds.
The pulse (y) is plotted as a function of x for t = 0. Draw the pulse (in the panels given)
(i) as a function of x for t = 0.04 s (ii) as a function of t for x = 0.

V = 150 m / s; x = v t; x = 150 \times \frac{4}{100} = 6 c m

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V = 120 m / s; x = v t; x = 150 \times \frac{4}{100} = 6 c m

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V = 150 m / s; x = v t; x = 120 \times \frac{4}{100} = 6 c m

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V = 150 m / s; x = v t; x = 150 \times \frac{4}{100} = 5 c m

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Solution

The correct option is A $V = 150 m / s; x = v t; x = 150 \times \frac{4}{100} = 6 c m$
The pulse $y$ is ploted as a function of $x$ for $t = 0$ in the top pannel can be converted into the plot $(y - x)$ and $(y - t)$ shown in second and third pannel.

For wave Velocity at $x = o m$
$x - 150 t = 0 \frac{x}{t} = 150 = v v = 150 m s^{- 1}$
Displacement at $t = 0.04 s e c$
$x = 150 t x = 150 \times 0.04 x = 6 c m$ .

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