A pump can rise 600 kg of water from well to an average of 20 m/s.
If efficiency of the pump is 70 %. Find its power in HP. Please show the full working.

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Solution

Given:-
Mass, m= 600 kg
Average Velocity ,V avg= 20 m/s
Effiiciency , η = 70%=0.70
Power, p=?
Power is the rate of doing work , p= W/t= Fd/t= F v
P= F V avg= mg* V avg [ F= mg]
P= 600Kg 9.8 m/s^2 20 m/s= 117600 Watts
Effiiciency , η = output power / input power
0.70= output power / 117600 Watts
Output Power= 0.70* 117600 watts = 82320 watts
Power in HP = 82320 watts/ 746 = 110. 3 Hp [ 1 hp= 746 watts]

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