An engine of $4.9 k W$ power is used to pump water from a well which is $20 m$ deep. What quantity of water in kiloliters can it pump out in $30$ minutes?

45 k l

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75 k l

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25 k l

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90 k l

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Solution

The correct option is A $45 k l$
Power $= \frac{w o r k}{t i m e} = \frac{m g h}{t}$
$= \frac{4.9 \times 10^{3} \times 30 \times 60}{9.8 \times 20} = m$
$m = 45 k l$

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An engine of 4.9kW power is used to pump water from a well which is 20m deep. What quantity of water in kiloliters can it pump out in 30 minutes?

The correct option is A 45klPower=worktime=mght=4.9×103×30×609.8×20=mm=45kl

An engine of $4.9 k W$ power is used to pump water from a well which is $20 m$ deep. What quantity of water in kiloliters can it pump out in $30$ minutes?

The correct option is A $45 k l$
Power $= \frac{w o r k}{t i m e} = \frac{m g h}{t}$
$= \frac{4.9 \times 10^{3} \times 30 \times 60}{9.8 \times 20} = m$
$m = 45 k l$