An engine of 4.9 kilowatt power is used to pump water from a well 50 meter deep. Calculate the quantity of water in kilolitres which it can pump out in one hour.

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Solution

Power (P) $= 4.9 k i l o w a t t$
$= 4.9 \times 1000 w a t t$
$= 4900 w a t t s$
Depth of a well (h) $=$ 50 meter
Acceleration due to gravity
$g = 9.8 m s^{- 2}$
$t = 1 h o u r$
$= 60 \times 60 = 3600 s$
$P = \frac{w o r k d o n e}{t i m e} = \frac{m g h}{t}$
$4900 = \frac{m \times 9.8 \times 50}{3600}$
$3600 \times 4900 = m \times 9.8 \times 50$
$m = \frac{3600 \times 4900}{9.8 \times 50} = 36000 k g$
$∴$ Volume of water pumped per hour
$= 36000 l i t r e$
$= 36.0 l i t r e$ ( $∴$ 1 litre $=$ 1 kg)
$= 36 k i l o l i t r e$

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