A pump ejects $12000 k g$ of water at the speed of $4 m / s$ in $40 s e c o n d .$ Find the average rate at which the pump is working

2.4 k w

Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses

2.5 k w

No worries! We‘ve got your back. Try BYJU‘S free classes today!

2.3 k w

No worries! We‘ve got your back. Try BYJU‘S free classes today!

1.7 k w

No worries! We‘ve got your back. Try BYJU‘S free classes today!

Open in App

Solution

The correct option is A $2.4 k w$
$F = m a = 12000 \times \frac{4}{40} = 1200 N$
$A = F / m = 1200 / 1200 = 1 / 10 m / s^{2}$
$s = u t + \frac{1}{2} a t^{2} = 0 + \frac{1}{2} \times \frac{1}{10} \times 40 \times 40 = 80 m$
then, $W = F s = 80 \times 1200 = 96000 J$
rate of working, $P = \frac{W}{t}$
$P = \frac{96000}{40} = 2400 W = 2.4 k W$

Suggest Corrections

Similar questions

10 m / s

[g = 10 m / s^{2}]

2.5 m

10 c m^{2}

5 m / s

A pump is used to lift 500 kg of water from a depth of 80 m in 10 s.Calculate:

(a) the work done by the pump,

(b) the power at which the pump works, and

10 m / s

[g = 10 m / s^{2}]

Join BYJU'S Learning Program