A pump is pumping water from the well at a depth of 8 m at the rate of 5 kg per second. The speed of water coming out is $10 m / s$ . The power of the pump is $[g = 10 m / s^{2}]$

550 W

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400 W

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800 W

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650 W

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Solution

The correct option is D 650 W
$Power = \frac{work done on gravity + change in KE}{time} Power = \frac{m g h + \frac{1}{2} m v^{2}}{t} = \frac{m}{t} (g h + \frac{v^{2}}{2}) = 5 ((10 \times 8) + \frac{10^{2}}{2}) P o w e r = 400 + 250 = 650 W a t t$

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Similar questions

Q. A pump is pumping water from the well at a depth of 8 m at the rate of 5 kg per second. The speed of water coming out is

10 m / s

. The power of the pump is

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A pump is pumping water from the well at a depth of 8 m at the rate of 5 kg per second. The speed of water coming out is 10m/s. The power of the pump is [g=10m/s2]

The correct option is D 650 WPower=work done on gravity + change in KEtimePower=mgh+12mv2t=mt(gh+v22)=5((10×8)+1022)Power=400+250=650 Watt

A pump is pumping water from the well at a depth of 8 m at the rate of 5 kg per second. The speed of water coming out is $10 m / s$ . The power of the pump is $[g = 10 m / s^{2}]$

The correct option is D 650 W
$Power = \frac{work done on gravity + change in KE}{time} Power = \frac{m g h + \frac{1}{2} m v^{2}}{t} = \frac{m}{t} (g h + \frac{v^{2}}{2}) = 5 ((10 \times 8) + \frac{10^{2}}{2}) P o w e r = 400 + 250 = 650 W a t t$