A pump of 200 W power is lifting 2 kg water per second from an average depth of 10m. The velocity with which water comes out of the pump is. (g = 9.8 $m / s^{2}$ )

Open in App

Solution

Energy spent by pump is used in lifting water against gravity as well as giving kinetic energy to it.

$⟹ m g h + \frac{1}{2} m v^{2} = 200$

$⟹ 2 \times 9.8 \times 10 + \frac{1}{2} \times 2 v^{2} = 200$

$⟹ v^{2} = 4$

$⟹ v = 2 m / s$

Suggest Corrections

Similar questions

A pump of $200 W$ power is lifting $2 k g$ water per second from an average depth of $10 m$ . The velocity with which water comes out of the pump is :

$(g = 9.8 m s^{- 2})$ .

Q. A pump of 200 W power is lifting 2 kg water per second from an average depth of 10m.

Q. A pump of

200 W

power is lifting

2 k g

water from an average depth of

10 m

in one second. Velocity of water delivered by the pump is :

(g = 10 m / s^{2})

Q. A pump is pumping water from the well at a depth of 8 m at the rate of 5 kg per second. The speed of water coming out is

10 m / s

. The power of the pump is

[g = 10 m / s^{2}]

Q. A pump is pumping water from the well at a depth of 8 m at the rate of 5 kg per second. The speed of water coming out is

10 m / s

. The power of the pump is

[g = 10 m / s^{2}]

Join BYJU'S Learning Program

A pump of 200 W power is lifting 2 kg water per second from an average depth of 10m. The velocity with which water comes out of the pump is. (g = 9.8 m/s2)

Energy spent by pump is used in lifting water against gravity as well as giving kinetic energy to it.⟹mgh+12mv2=200⟹2×9.8×10+12×2v2=200⟹v2=4⟹v=2m/s

A pump of 200 W power is lifting 2 kg water per second from an average depth of 10m. The velocity with which water comes out of the pump is. (g = 9.8 $m / s^{2}$ )

Energy spent by pump is used in lifting water against gravity as well as giving kinetic energy to it.

$⟹ m g h + \frac{1}{2} m v^{2} = 200$

$⟹ 2 \times 9.8 \times 10 + \frac{1}{2} \times 2 v^{2} = 200$

$⟹ v^{2} = 4$

$⟹ v = 2 m / s$